One of Hottest for Oil Tank Gauge Not Working - OR-MULTI-TUBE Series Oil Pressure Cooler – Xinyuan

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One of Hottest for Oil Tank Gauge Not Working - OR-MULTI-TUBE Series Oil Pressure Cooler – Xinyuan Detail:

1. Heat transfer to determine the best cooling effect. This cooler adopts multi-tube type, large cooling area, Good cooling effect.

2. The cooling area is full. The cooling area is calculated according to the surface area of the copper tube, so the cooling area is full.

3. Cooler material is most suitable for heat dissipation. Adopt pure red copper tube, heat conductivity is above 0.95.

1. the cooling pipe oil two can freely decide the inlet and outlet, the flow of oil itself is not restricted. The inlet of water must be entered from the bottom and discharged from the upper outlet.
2. Fresh water only. The use of sea water shall be specially customized.
3. Food and chemicals must not be used.
4. water inlet and oil inlet temperature difference in more than 80°C can not be used.
5. the highest pressure: oil side 10kg/cm2, water side 7kg/cm2
6. the water side (heat transfer tube inner surface) for about 4 months or half a year, remove scale once, can maintain a good cooling efficiency. When using high viscosity oil, please keep the amount of oil equal to the amount of water.

opc1

Model	A	B	C	ΦD	E	F	G	J	K	4>L	M	N	Traffic
OR-60	450	305	46	90	120	3/4″	3/4″	23	11	115.5	95	7×10	60
OR-100	555	403	57	114	150	3/4″	3/4″	33	12.5	145.5	106.5	10×20	100
OR-150	575	385	76	140	180	11/4″	1″	30	12.5	175	130	13×16	150
OR-250	780	585	76	140	180	11/4″	1″	30	12.5	175	130	13×16	250
OR-350	1180	990	76	140	180	11/4″	1″	30	12.5	175	130	13×16	350
OR-600	1175	950	87	165	205	T	11/4¹¹	34	12.5	200	161	13×16	600
OR-800	1700	1490	87	165	205	T	11/4^“	34	12.5	200	161	13×16	800
OR-1000	2140	1890	87	165	205	T	11/4″	34	12.5	200	161	13×16	1000

opc2

Model	L	Cl	C	L2	LI	H2	B	C2	n-b x I	Hl	D2	DI	（12	dl	Weight （Kg）
SL-303	305	45	152	107	80	85	115	75	4-11×20	64	120	87.9	G3/4	G3/4	4.5
SL-304	377		224	179											5
SL-305	450		296	251											5.5
SL-307	593		440	395											6
SL-309	737		584	539											7
SL-311	880		728	683											8
SL-408	467	75	284	240	94	100	150	110	4-10×20	85	160	121	G1 1/4	G3/4	14
SL-411	610		428	384											17
SL-415	755		572	528											19
SL-418	900		716	672											22
SL-421	1042		860	816											25
SL-512	528	70	298	206	121	140	180	135	4-18×25	95	180	139.8	G1 1/2	G1	20
SL-518	635		406	342											22
SL-526	852		622	558											27
SL-534	1070		838	774											32
SL-542	1285		1054	990											38

Note: our company can manufacture all kinds of large and special coolers according to the requirements of customers.

opc3

1. Calculate the heat required to exchange:

Q(Kcal /h) (1) Calculate according to the temperature requirements and flow of the oil: Q is CW of N dot T2.In the formula, the specific heat of C oil (kCa L/kg°C) W — the flow rate of oil (kg/h)T1 — inlet oil temperature (°C) T2 — outlet oil temperature (°C)Among them: W = qPIn the formula, Q — flow rate of oil (IV min) P — density of oil (kg/L)According to the calorific value of the hydraulic system: Q = Pr-Pc-PhcWhere, PR is the input power of the hydraulic system PHC one tank, pipe heat dissipation power PC – output effective power.

2. Select the cooler model

Check the product performance curve according to the calculated heat exchange Q and oil flow Ws, and the intersection point of the two is the selected model.

3. Supplementary Notes

The actual operating conditions of the cooler may differ from their performance test conditions. The oil viscosity is small, the water flow is large, the temperature difference between the oil temperature and the water temperature is large, the model can be selected to be smaller than the selected model, on the contrary, the model is selected to be large.

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